## 数学代写|微积分代写Calculus代写|MTH263

2023年1月5日

couryes-lab™ 为您的留学生涯保驾护航 在代写微积分Calculus方面已经树立了自己的口碑, 保证靠谱, 高质且原创的统计Statistics代写服务。我们的专家在代写微积分Calculus代写方面经验极为丰富，各种代写微积分Calculus相关的作业也就用不着说。

• Statistical Inference 统计推断
• Statistical Computing 统计计算
• (Generalized) Linear Models 广义线性模型
• Statistical Machine Learning 统计机器学习
• Longitudinal Data Analysis 纵向数据分析
• Foundations of Data Science 数据科学基础
couryes™为您提供可以保分的包课服务

## 数学代写|微积分代写Calculus代写|Trig antiderivatives

As previously stated, all derivative formulas can be reversed to provide antiderivative formulas. An example involving trigonometric functions is the derivative formula
$$\frac{d}{d x} \tan x=\sec ^2 x$$
which yields
$$\int \sec ^2 x d x=\tan x+C$$
When the derivative formula results in the use of a negative sign, a slight adjustment is helpful. Reversing $\frac{d}{d x} \cos x=-\sin x$ gives $\int(-\sin x) d x=\cos x+C$, which is not convenient to use because of the negative sign. If we differentiate negative cosine instead, we get a more convenient form. Reversing
$$\frac{d}{d x}(-\cos x)=\sin x$$
yields the antidifferentiation formula
$$\int \sin x d x=-\cos x+C$$
All six trig derivatives can be reversed in this manner.

The indefinite integral formulas (antiderivative formulas) in the right-most column should be memorized, because each formula is used repeatedly for the remainder of this book.
Example 13 Evaluate the indefinite integral $\int\left(4 \sin x+\sec ^2 x\right) d x$.
Solution Using the formulas for the antiderivatives of $\sin x$ and $\sec ^2 x$, along with the antiderivative sum rule and the antiderivative constant multiple rule, gives
\begin{aligned} \int\left(4 \sin x+\sec ^2 x\right) d x & =4(-\cos x)+\tan x+C \ & =-4 \cos x+\tan x+C . \end{aligned}

## 数学代写|微积分代写Calculus代写|Estimating areas using rectangles

The area of the green-shaded region in figure 1 is commonly described as the area under the curve $y=x^2$ from $x=1$ to $x=5$. When we use this terminology, we need a curve that lies on or above the $x$-axis, and the region is then between the $x$-axis and the curve.

Although the area formulas from geometry do not apply to this region directly, we can use the formulas to attempt to estimate the area. Perhaps the easiest area formula is the one for a rectangle. To use the rectangle area formula, we need to decide how many rectangles to use and where to place them. If we use $n=4$ rectangles of width 1 and let the height of each rectangle match the height of the curve at the upper left corner of the rectangle (figure 2, right), we can then estimate the area under the curve by finding the total area of the four rectangles.

To calculate the total area of the brown rectangles in figure 2, we need to know both the widths and the heights of the rectangles. The width of each rectangle is 1 . Notice that the total width of the region is $5-1=4$ and there are four rectangles. In general, if the region goes from $x=a$ to $x=b$ and there are $n$ rectangles, the width of each rectangle is given by
$$\text { width }=\Delta x=\frac{b-a}{n} .$$
Here, the width of each rectangle is $\Delta x=\frac{b-a}{n}=\frac{5-1}{4}=1$.
We can think of each rectangle as being placed on a subinterval of the region’s interval. In figure 2, left, the green region’s interval along the $x$-axis is the interval from $x=1$ to $x=5$, or the interval $[1,5 \mid$. The brown rectangles in figure 2, right, are placed on the subintervals $[1,2],[2,3],[3,4]$, and $[4,5]$. The heights of the rectangles then match the heights of the curve at the left-hand endpoint of each subintervalthat is, at $x=1, x=2, x=3$, and $x=4$. Because the curve is $y=x^2$, the heights of the rectangles are $y=1^2=1, y=2^2=4, y=3^2=9$, and $y=4^2=16$ (figure 3 ).

We are finally ready to calculate the total area of the brown rectangles. Using the formula $A=w h$ for the area of a rectangle, the areas of the rectangles are $1 \cdot 1,1 \cdot 4,1 \cdot 9$, and $1 \cdot 16$. The total area is
$$1 \cdot 1+1 \cdot 4+1 \cdot 9+1 \cdot 16=30 \text { units }^2$$

# 微积分代考

## 数学代写|微积分代写Calculus代写|Trig antiderivatives

$$\frac{d}{d x} \tan x=\sec ^2 x$$

$$\int \sec ^2 x d x=\tan x+C$$

$$\frac{d}{d x}(-\cos x)=\sin x$$

$$\int \sin x d x=-\cos x+C$$

$$\int\left(4 \sin x+\sec ^2 x\right) d x=4(-\cos x)+\tan x+C$$

## 数学代写|微积分代写Calculus代写|Estimating areas using rectangles

$$\text { width }=\Delta x=\frac{b-a}{n} .$$

$$1 \cdot 1+1 \cdot 4+1 \cdot 9+1 \cdot 16=30 \text { units }^2$$

## 有限元方法代写

tatistics-lab作为专业的留学生服务机构，多年来已为美国、英国、加拿大、澳洲等留学热门地的学生提供专业的学术服务，包括但不限于Essay代写，Assignment代写，Dissertation代写，Report代写，小组作业代写，Proposal代写，Paper代写，Presentation代写，计算机作业代写，论文修改和润色，网课代做，exam代考等等。写作范围涵盖高中，本科，研究生等海外留学全阶段，辐射金融，经济学，会计学，审计学，管理学等全球99%专业科目。写作团队既有专业英语母语作者，也有海外名校硕博留学生，每位写作老师都拥有过硬的语言能力，专业的学科背景和学术写作经验。我们承诺100%原创，100%专业，100%准时，100%满意。

## MATLAB代写

MATLAB 是一种用于技术计算的高性能语言。它将计算、可视化和编程集成在一个易于使用的环境中，其中问题和解决方案以熟悉的数学符号表示。典型用途包括：数学和计算算法开发建模、仿真和原型制作数据分析、探索和可视化科学和工程图形应用程序开发，包括图形用户界面构建MATLAB 是一个交互式系统，其基本数据元素是一个不需要维度的数组。这使您可以解决许多技术计算问题，尤其是那些具有矩阵和向量公式的问题，而只需用 C 或 Fortran 等标量非交互式语言编写程序所需的时间的一小部分。MATLAB 名称代表矩阵实验室。MATLAB 最初的编写目的是提供对由 LINPACK 和 EISPACK 项目开发的矩阵软件的轻松访问，这两个项目共同代表了矩阵计算软件的最新技术。MATLAB 经过多年的发展，得到了许多用户的投入。在大学环境中，它是数学、工程和科学入门和高级课程的标准教学工具。在工业领域，MATLAB 是高效研究、开发和分析的首选工具。MATLAB 具有一系列称为工具箱的特定于应用程序的解决方案。对于大多数 MATLAB 用户来说非常重要，工具箱允许您学习应用专业技术。工具箱是 MATLAB 函数（M 文件）的综合集合，可扩展 MATLAB 环境以解决特定类别的问题。可用工具箱的领域包括信号处理、控制系统、神经网络、模糊逻辑、小波、仿真等。